7p^2+9p+6=4

Solution for 7p^2+9p+6=4 equation:

7p^2+9p+6=4

We move all terms to the left:

7p^2+9p+6-(4)=0

We add all the numbers together, and all the variables

7p^2+9p+2=0

a = 7; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·7·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*7}=\frac{-14}{14}
=-1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*7}=\frac{-4}{14}
=-2/7
$